Solve Matrix Y+3z=5 2x+2y=11 3x+2z=13

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1 Answer

Cramer's Method:

Δ=

⎜0 1 3⎟

⎜2 2 0⎟= 0-4+3(-6)=-22.

⎜3 0 2⎟

Δx=

⎜  5 1 3⎟

⎜11 2 0⎟= 20-22-78=-80,

⎜13 0 2⎟

x=Δx/Δ=-80/(-22)=40/11.

Δy=

⎜0   5 3⎟

⎜2 11 0⎟= 0-20-21=-41,

⎜3 13 2⎟

y=Δy/Δ=-41/(-22)=41/22.

Δz=

⎜0 1   5⎟

⎜2 2 11⎟= 0+7-30=-23,

⎜3 0 13⎟

z=Δz/Δ=-23/(-22)=23/22.
SOLUTION: x=40/11, y=41/22, z=23/22.
by Top Rated User (1.2m points)

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