find the values of x such that f(x)=1 ... the equation for it is 3x^2-33x+91.

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find the values of x such that f(x)=1 ... the equation for it is 3x^2-33x+91.
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1 Answer

f(x)=3x^2-33x+91=1, 3x^2-33x+90=0, x^2-11x+30=0=(x-5)(x-6).

So x=5 or 6 and f(5)=f(6)=1.
by Top Rated User (1.2m points)

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