how to convert the standard form 10x-8y=-2 into slope intercept form

Question

i need to convert standard form to slope intercept form

Answer 1

Find the intercepts of 10x-8y=-2: y=0 gives the x-intercept,10x=-2, x=-2/10=-⅕.

x=0 gives the y-intercept: -8y=-2, y=¼.

Slope is found by taking the intercepts as the points (-⅕,0) and (0,¼) and working out the slope between them: (¼-0)/(0-(-⅕))=¼/⅕=5/4  [(difference of y-coords)/(difference of x-coordinates)].

Slope-intercept form: y-0=(5/4)(x-(-⅕)), y=(5/4)(x+⅕).

(This is the same as y=5x/4+¼, 4y=5x+1 or 5x+1-4y=0, 5x-4y+1=0, 5x-4y=-1. Doubled, this is 10x-8y=-2, the given equation.)