First, let's put x=0 in the proposed equality, then 2x=20=1:
5×1-1-2=1 is not true so the equality is false. The proposed equality is not true.
5×2x-2x-2=4×2x-2=22×2x-2=2x+2-2=2(2x+1-1). So the RHS=2, 6, 14, 30, as x=0, 1, 2, 3.
There is an error in the question or the question has been wrongly expressed.
(5×2x-2x)/22=2x, for example, is true.