find the area of the shaded space and the perimeter of the small rectangle

rectangle boxes inside one another, first box L 7m on both sides and W 6m on both sides, inside box L 5m on both sides and W 4m on both sides
in order of operations by

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1 Answer

No matter how the boxes are arranged the difference in area is always 7*6-5*4=42-20=22sq m. The perimeter of the small box is twice the sum of length and width=2(5+4)=18m.

by Top Rated User (1.2m points)

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