series from n=1 to infinity of (1/ln(n+2)-1/ln(n+1)) converge or diverge

series from n=1 to infinity of (1/ln(n+2)-1/ln(n+1)) converge or diverge
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All the terms cancel out except the first term -1/ln(2) and the last which is 0 because the denominator goes to infinity. Therefore the answer is the series converges to -1/ln(2)=-log₂e=-1.4427 approx.

by Top Rated User (1.2m points)

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