Last year: g(x)=-4x4+6x(4x-1)-4; this year: f(x)=-3x2(x2-8)-6x-5,
Last year: g(x)=-4x4+24x2-6x-4; this year f(x)=-3x4+24x2-6x-5.
We need to know when f(x)>g(x), that is, f(x)-g(x)>0.
Therefore: -3x4+24x2-6x-5-(-4x4+24x2-6x-4)>0,
-3x4+24x2-6x-5+4x4-24x2+6x+4>0,
x4-1>0, x4>1⇒x>1, because x has to be positive since it's a quantity of videos. So this year's revenue exceeds last year's provided more than 1,000 videos are sold (revenue exceeds $10M).
[However, it should be noted that the net revenue for the two years can be a loss if the quantity of videos exceeds a certain amount. For last year, this would have been x=2.268 (2,268 videos) and for this year x=2.647 (2,647 videos). Nevertheless, this year's revenue still exceeds last year's (and losses are not as great).]