find the slope-intercept equation of the line with the following properties:

perpendicular to the line x-4y=7; containing the point (3,4)
in Algebra 2 Answers by Level 3 User (2.2k points)

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1 Answer

The line x - 4y = 7 has slope. . .

x - 4y = 7

-4y = -x + 7

y = (1/4)x - 7

slope = 1/4

.

Perpendicular lines have slopes that are flipped as fractions (1/4 becomes 4/1) and as +- signs (4/1 becomes -4/1).

Our new slope is -4/1 or just -4.

.

So our goal is to find the slope intercept form of the line passing through (3,4) with slope -4.

Point-slope form:

y - y1 = m(x - x1)

y - 4 = -4(x - 3)

y - 4 = -4x + 12

y = -4x + 16

by Level 13 User (103k points)

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