find an equation for the circle with center (5,3) and whose graph contains the point (-3,9)

Question

need help with this question!

Answer 1

The equation is (x-5)²+(y-3)²=r², because the equation of a circle with centre at the x-y origin is x²+y²=r² where r is the radius. So the equation is adjusted to make the origin (5,3) instead of (0,0). To find r, simply substitute x=-3 and y=9:

(-8)²+(6)²=r², making r²=64+36=100 (r=10).

Equation is (x-5)²+(y-3)²=100

Comments

thank you!