Philip made a total of 9 bracelets and necklaces from 120 inches of cord.
He used 8 inches of cord for each bracelet and 20 inches of cord for each necklace.
Use matrices to find the number of bracelets and the number of necklaces that Philip made.

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1 Answer

B=number of bracelets, N=number of necklaces.

B+N=9 (total number)

8B+20N=120 (total length of cord).

Matrix is:

⎛ 1   1 ⎞

⎝ 8 20 ⎠

Determinant Δ is 1×20-8×1=12.

Replace the first column with the numbers (total and cord length):

⎛ 9       1 ⎞

⎝ 120 20 ⎠

B-determinant ΔB=9×20-120×1=60, B=ΔB/Δ=60/12=5.

Replace the second column with the same numbers:

⎛ 1     9 ⎞

⎝ 8 120 ⎠

N-determinant ΔN=120-72=48, N=ΔN/Δ=48/12=4.

CHECK

B+N=5+4=9, 8B+20N=40+80=120 inches. This confirms 5 bracelets and 4 necklaces.

by Top Rated User (1.2m points)

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