A survey of 254 randomly chosen residents in a city revealed that 4 had four tv sets, 22 has three sets, 83 has two sets, 140 had one set and 5 had no tv sets. Based on the survey. Calculate to two decimal accuracy:

What is the simple average of tv sets per household?

What is the weighted average tv sets per household?
in Algebra 2 Answers by Level 1 User (440 points)
reshown by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

If we ignore how many households (residents) had the various numbers of TV sets then the simple average is:

(4+3+2+1+0)/5=10/5=2 or 2.00 TV sets.

The weighted average would take into account how many households had each of the various numbers of TV sets. There are:

4×4+22×3+83×2+140×1+5×0=16+66+166+140+0=388 TV sets.

The number of households is 254, so the weighted average is 388/254=194/127=1.53 TV sets to 2 decimal places.

(Note that rounded to the nearest whole number, the weighted and simple averages are the same.)

by Top Rated User (1.2m points)

Related questions

0 answers
asked Apr 6, 2013 in Calculus Answers by anonymous | 478 views
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,516 questions
100,279 answers
2,420 comments
732,382 users