Use the primary trigonometry ratios to prove that tanAcosA = sinA

Use the primary trigonometry ratios to prove that tanAcosA = sinA
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tanA = sinA/cosA, so cosAtanA=tanAcosA=sinA by multiplying through by cosA.

Or since tan=opposite/adjacent, cos=adjacent/hypotenuse and sin=opposite/hypotenuse, sin/cos=opposite/adjacent because hypotenuse cancels out. Therefore tan=sin/cos, or tanAcosA=sinA.

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