v=ds/dt=∆s/∆t approximately where s is distance, and ∆s and ∆t are small increments of distance and time. So ∆s=v∆t. ∆t is the difference between consecutive values of t in the table. ∆t=0.2 (fixed). We could use v as the average v(t) between two consecutive values of v(t) corresponding to the consecutive values of t.
With that information, we can piece together s from a sequence of ∆s values.
A system abnormality (which I understand is receiving attention) is preventing me from inserting the table, so I will just type out the last column which is ∆s:
0.03280
0.05057
0.05118
0.04998
0.05074
0.05561
0.06600
0.08283
0.10660
0.14013
TOTAL s=0.68644