The range of the quadratic function y=〖-3(x+7)〗^2+8 is ( {y/y≥8} , {y/y≤8} ).

The choices are the  ( {y/y≥8} , {y/y≤8} ).
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1 Answer

y=[(3(x+7)]²+8 has a range [8,∞). There is no upper limit and the minimum value of 8 occurs when x=-7. So y≥8.

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