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o = AE(0.405D1 + 0.096D2)
-2 = AE(0.096Dl + 0.128D2)

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1 Answer

If AE is a function, it hasn’t been defined.

Assume there’s an inverse AE⁻¹.

(1) AE⁻¹(0)=0.405D1+0.096D2

(2) AE⁻¹(-2)=0.096D1+0.128D2

(3) 4(1): 4AE⁻¹(0)=1.62D1+0.384D2

(4) 3(2): 3AE⁻¹(-2)=0.288D1+0.384D2

(3)-(4): 4AE⁻¹(0)-3AE⁻¹(-2)=1.332D1,

D1=(4AE⁻¹(0)-3AE⁻¹(-2))/1.332.

(5) 0.032AE⁻¹(0)=0.01296D1+0.003072D2

(6) 0.135AE⁻¹(-2)=0.01296D1+0.01728D2

(6)-(5): -0.032AE⁻¹(0)+0.135AE⁻¹(-2)=0.014208D2,

D2=(0.135AE⁻¹(-2)-0.032AE⁻¹(0))/0.014208.

Solution:

D1=(4AE⁻¹(0)-3AE⁻¹(-2))/1.332,

D2=(0.135AE⁻¹(-2)-0.032AE⁻¹(0))/0.014208.

by Top Rated User (1.2m points)

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