let the joint probability mass function of and y is

P(x,y)=x+y/21 x=1,2,3 y=1,2 find Var(Y|X = 1)
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1 Answer

 

     
x↓y→ 1 2 TOTAL
1 2/21 1/7 5/21
2 1/7 4/21 1/3
3 4/21 5/21 3/7
TOTAL 3/7 4/7 1

Table shows all possibilities and validates P(x,y)=(x+y)/21 because ∑P(x,y)=1 for X∈{1,2,3} and Y∈{1,2}.

When X=1, we can find E[Y]=1(2/21)+2(1/7)=2/21+2/7=8/21.

E[Y²]=1(2/21)+4(1/7)=2/21+4/7=14/21=2/3.

VAR=2/3-(8/21)²=230/441.

 

by Top Rated User (1.2m points)

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