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1 Answer

y-intercept occurs at x=0, and x-intercept occurs at f(x) =0

f(x) =3x^2 -20x+12

f(0) = 12

(5) (0,12)

3x^2 -20x+12=0

D = b^2 - 4ac

D = (-20)^2 - 4*3*12 = 256

x = (-b +- sqrt(D))/2a

x = (20 +- 16)/2*3

so x = 2/3 or x= 6

(6) (2/3,0)(6,0)

f(x) = 15+2x-x^2

f(0) =15

7) (0,15)

15+2x-x^2=0

using quadratic formula we get:

x= -3 or x=5

(8) (-3,0)(5,0)

by Level 7 User (25.9k points)

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