Evaluate double integral

https://i.imgur.com/yzHuJEq.png

 

Just checking, is the answer 1.72?

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1 Answer

Yes, the answer is e-1=1.72 to 2 decimal places.

∬e^x²dydx.

Inner integral [0,2x] is [ye^x²]²ˣ₀=2xe^x².

Outer integral [0,1] is [e^x²]¹₀=e-1.

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