6/x^2-1/x-3=1

what is x i have to solve for x
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1 Answer

Let y=1/x then 6y2-y-3=1,

6y2-y-4=0, use the quadratc formula:

y=(1±√(1+96))/12=(1+√97)/12 or (1-√97)/12.

x=12/(1+√97) or 12/(1-√97).

x=12(1-√97)/(-96)=⅛(√97-1) or 12(1+√97)/(-96)=-⅛(√97+1).

by Top Rated User (1.2m points)

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