Given (0;2) is the function discontinuous
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f(x)=1/(2-4cos(2x)) has a discontinuity when the denominator is zero.

Assuming you mean the interval [0,2π], 4cos(2x)=2 at the discontinuity.

So cos(2x)=½, 2x=π/3 or 60º, so x=π/6 (30º).

But cos(2x)=½ when 2x=2π-π/3=5π/3 (300º). So x can also be 5π/6 (150º). Between π/6 and 5π/6 it’s continuous.

by Top Rated User (1.2m points)

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