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2 Answers

Your picture has low resolution so I can’t read the limits clearly. But my guess is:

a) Limit as x→0.

√(1+x)=1+x/2 to a first approximation, therefore (√(1+x)-1)/x=(x/2)/x=½. So the limit is ½.

b) Limit as x→∞? I also assume numerator is 4x²+x+1.

(4x²+x+1)/(1-x²)≈4x²/-x²=-4 (when x is very large). So limit =-4.

c) When x=3⁻, f(x)→11, when x=3⁺, f(x)→11, so as x→3, limit is 11.

by Top Rated User (1.1m points)

It is 4x^3+x+1 and not 4x²+x+1.

It is very difficult to see, but I somehow figured it out.

Solution to 4a:

https://ibb.co/dgRfTpm

Solution to 4b and 4c

https://ibb.co/p3N0G4w

by Level 8 User (30.1k points)

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