Evaluate limt→−2 (t^2+5t+7)

Evaluate  limt→−2 (t^2+5t+7)
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3 Answers

Since t^2+5t+7 is a continuous function, you can substitute t= -2 directly.

(-2)^2 +5*(-2) +7

=> 4 -10 +7

=> 1

by Level 8 User (30.1k points)

Limit obtained by direct substitution: 

(-2)²+5(-2)+7=4-10+7=1. Limit is 1.

by Top Rated User (1.2m points)
$x^2$
by

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