Find the perimeter of  a rectangle if three of its corners are (-3, 2), (7,- 2), and (-3,-2).

in Algebra 1 Answers by Level 1 User (120 points)

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

The missing vertex is (7,2). So the vertices are:

(-3,2), (7,2), (7,-2), (-3,-2) and the dimensions of the rectangle are: 7-(-3)=10 by 2-(-2)=4.

The perimeter is 2(7+4)=22 units.
by Top Rated User (1.2m points)

Related questions

1 answer
asked Aug 28, 2012 in Word Problem Answers by anonymous | 2.3k views
1 answer
asked Sep 30, 2013 in Calculus Answers by Tiff Huskey | 731 views
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,516 questions
100,279 answers
2,420 comments
733,129 users