In 3cosh2x = 3+sinh x, what is the value of x?
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1 Answer

3cosh2x = 3 + sinhx

3cosh2x -3 = sinhx

3(cosh2x-1) = sinhx

3sinh^2x = sinhx

3sinhx = 1

sinhx = 1/3

=>x = arcsinhx(1/3) = ln((1/3) + sqrt(x^2 +1))

or x = 0.327
by Level 4 User (5.8k points)
Line but the last should be x = arcsinhx(1/3) = ln((1/3) + sqrt((1/3)^2 +1))

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