(3x³-5x²+x-2)/(x(x-2)(x-1)²).
First, add the first two fractions: 1/x+2/(x-2)=(x-2+2x)/(x(x-2))=(3x-2)/(x(x-2)).
Now add to the third fraction:
(3x-2)/(x(x-2))+3/(x-1)²=((3x-2)(x-1)²+3x(x-2))/(x(x-2)(x-1)²)=
((3x-2)(x²-2x+1)+3x²-6x)/(x(x-2)(x-1)²)=
(3x³-6x²+3x-2x²+4x-2+3x²-6x)/(x(x-2)(x-1)²)=
(3x³-5x²+x-2)/(x(x-2)(x-1)²).