Sin(5x-28)°=cos(3x-50) °
in Trigonometry Answers by Level 4 User (7.5k points)
reopened by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

Best answer

The cosine of an angle is the same as the sine of its complement.

sin(5x-28)=sin(90-(3x-50)), 5x-28=90-3x+50, 8x=90+50+28=168, so x=21º. This is one of many answers.

The sine of an angle is also the sine of its supplement:

180-5x+28=90-3x+50, 180-90-50+28=2x, 68=2x, x=34º.

Other answers are 66º, 111º, etc, because of the cyclic nature of the harmonic functions.

by Top Rated User (1.2m points)
selected by
Thanks,I want to read more on this particular topic so help

To find all the angles we modify the above equations.

(1) 8x=168+360n, x=21+45n where n is any integer, positive or negative or zero. So we get the angles 21, 66, 111, 156, ... degrees from this formula. Also, -24, -69, ... degrees.

(2) The sine is positive in the first and second quadrant so the other formula is 2x=68+360n, x=34+180n and x=34, 214, 394, ..., -146, -326, ... degrees.

There are an infinite number of solutions.

No related questions found

Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,516 questions
100,285 answers
2,420 comments
734,801 users