(3x+2y)dx+2xdy=0

homogeneous equation
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1 Answer

(3x+2y)dx+2xdy=0,

2xdy+2ydx=-3xdx,

2d(xy)=-3xdx,

2xy=-3∫xdx=-3x²/2+C where C is constant of integration.

This can be written:

y=½C/x-¾x².

by Top Rated User (1.2m points)

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