Find dy/dx for the equation x^3-2x^2y+3xy^2=38

Differential equation
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3 Answers

dy/ dx = xy+2x-2y - 4

by
dy/dx = y+x+1/y+x+3
by
Given x^3 - 2x^2y + 3xy^2 = 38

we use implicit differentiation to solve for dy/dx to get

3x^2 - 4xy - 2x^2(dy/dx) + 3y^2 + 6xy(dy/dx) = 0

Solving for dy/dx gives

dy/dx = (-3x*2 + 4xy - 3y^2) / (-2x^2 + 6xy)

This is the CORRECT answer!
by Level 2 User (1.7k points)

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