Find the smallest number divisible by 225 that consists of only the digits 1 and 0.
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225=9×25. The product 225n must be divisible by both 9 and 25. If the product ends in two zeroes, then it’s divisible by 25. To be divisible by 9 there must be a minimum of nine 1s in the product, so the smallest product is 11,111,111,100. (Dividing this by 225 we get n=49,382,716.)

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