This problem is an algebra 1 question and it is about graphing equations.
in Algebra 1 Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

8 minutes=480 seconds.

If n is the number of times you run and t seconds is the time to run the distance, a linear relationship would be t=480-20n. From this equation, which graphs as a straight line, when n=480/20=24, t would be zero, so n=24 is the x-intercept and the y-intercept is 480 seconds (8 min) which is the starting point in time. The graph is the segment joining the intercepts. The model is clearly limited because no-one can run any distance in zero time. And neither t nor n can be negative.

(A better graphing model may be to consider 20 seconds as a fraction of the current running time, so that is 20/480=1/24 or about a 4% reduction in time. The mathematical model would be t=480(23/24)ⁿ. When n=1, t=460 seconds, 20 seconds short of 8 minutes. But when n=2, t=440.83 seconds, which is less than 20 seconds shorter. When n=24, t=172.8 secs approx. The graph is exponential and t is never zero, although it approaches zero when n is very large.)

by Top Rated User (1.2m points)

Related questions

2 answers
asked Oct 26, 2012 in order of operations by anonymous | 2.3k views
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,516 questions
100,279 answers
2,420 comments
732,258 users