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1 Answer

This looks like:

(4x)^⅓/(16x³)^¾=

(2²x)^⅓/(2⁴x³)^¾=

(2^⅔)(x^⅓)/(2³)(x^(9/4))=

(2^-(4/3))(x^(⅓-9/4))=

(2^-(4/3))(x^-(23/12)) or 1/((2^(4/3))(x^(23/12))).

by Top Rated User (776k points)

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