It's a differential equation
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(6x-2y-7)/(3y+2x+4)=dy/dx needs to be progressively reduced so that we can separate variables then integrate.


Let x=X+h and y=Y+k where h and k are constant displacements of the x and y axes. These displacements will enable the constants -7 and 4 to be removed so that we have a homogeneous expression in X and Y.

Substituting for x and y:


To remove the constants: 6h-2k=7 and 3k+2h=-4, which can be written 6h+9k=-12. Subtracting to eliminate h we get: 11k=-19, so k=-19/11 and h=(-4-3k)/2=(-4+57/11)/2=13/22.

Therefore dY/dX=(6X-2Y)/(3Y+2X).


Let Y=vX, then dY/dX=(6X-2vX)/(3vX+2X)=(6-2v)/(3v+2). dY/dX=v+Xdv/dX, where v=v(X), a function of X. Therefore, Xdv/dX=(6-2v)/(3v+2)-v=(6-2v-3v²-2v)/(3v+2). The variables can be separated and integration is possible:


So -2∫dX/X=ln|6-4v-3v²|. Therefore ln(a/X²)=ln|6-4v-3v²|, and a/X²=6-4v-3v², where a is the constant of integration. We can now substitute back to x and y. a/X²=6-4Y/X-3(Y/X)², a=6X²-4XY-3Y²=6(x-13/22)²-4(x-13/22)(y+19/11)-3(y+19/11)². 

This evaluates to:

6x²-4xy-3y²-14x-8y=C where C is a constant.


Differentiating we get:



Divide through by 2:

6x-2y-7=(dy/dx)(2x+3y+4), (6x-2y-7)/(3y+2x+4)=dy/dx, the original DE.

by Top Rated User (781k points)

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