195 miles apart, one traveling at 65mph, second traveling at 75mph
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If they meet at a distance x from where the slower motorcycle started, the time it takes the slower one to reach x is x/65 and the time the faster one to travel 195-x is (195-x)/75. They meet at the same time so:

x/65=(195-x)/75, 75x=12675-65x (cross-multiplying), 140x=12675, x=12675/140=90.54 miles approx.

Another way to solve is to divide the distance according to the ratio of their speeds. 65/140×195 and 75/140×195, that is, 2535/28=90.54, 2925/28=104.46 miles.

We have the distance so we can find the time = 2535/28÷65=2925/28÷75=1.39hrs, or 1hr 23.6min approx.

by Top Rated User (1.2m points)

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