The random variable X follows a Poisson process with the given value of

lambdaλ

and t. Assuming

lambdaλequals=0.130.13

and

tequals=1515,

compute the following.

(a)

P(55)

(b)

P(Xless than<55)

(c)

P(Xgreater than or equals≥55)

(d)

P(33less than or equals≤Xless than or equals≤77)

(e) mu Subscript Upper X Baseline and sigma Subscript Upper X

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1 Answer

Po(X)=(λt)ᵡe^-(λt)/X! µ=σ²=λt=0.13×15=1.95.

a) Po(X=5)=1.95⁵e⁻¹⋅⁹⁵/5!=0.03343.

b) Po(<5)=Po(0)+Po(1)+Po(2)+Po(3)+Po(4)=

0.14227+0.27743+0.27050+0.17582+0.08571=0.95175 approx. (95.18%)

c) Po(≥5)=1-0.95175=0.04825 approx. (4.83%)

d) Po(3≤X≤7)=Po(3)+Po(4)+Po(5)+Po(6)+Po(7)=

0.17582+0.08571+0.03343+0.01086+0.00303=0.30886 approx. (30.89%)

e) µ=1.95, σ=√1.95=1.40 approx.

by Top Rated User (1.2m points)

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