I read this as y=½x-3y=(3/2)x-1.
From the first equation, y=½x-3y, add 3y to each side: 4y=½x. Divide each side by 4: y=x/8=(3/2)x-1.
Therefore x/8=(3/2)x-1. Multiply both sides by 8: x=12x-8, subtract x from each side: 0=11x-8. Add 8 to each side: 8=11x, and dividing through by 11, we get 8/11=x, or x=8/11, so y=1/11. Graphically, this is a point of intersection (8/11,1/11) of y=⅛x and y=³⁄₂x-1: