maximum height of ball -4.9t^2+6 t+.6

Find the maximum height of the ball kicked with the projection - h(t) -4.9t^2+6 t+.6
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Differentiate h: -9.8t+6=0 at maximum height, so t=6/9.8 and h(6/9.8)=2.4367 approx.

 

 

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