Solve the following systems of equations.


in Algebra 2 Answers by Level 1 User (300 points)

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1 Answer

There are a number of ways of solving this system. Here’s one.

Label the equations:

(1) 4y+3z=-7

(2) 12x-3y+z=-7

(3) -6x+2y-2z=12

(4): (2)+2(3): y-3z=17

(5): (4)+(1): 5y=10, so y=2

From (1) 3z=-7-4y=-7-8=-15, so z=-15/3=-5.

From (2) 12x=-7+3y-z=-7+6+5=4, x=4/12=⅓.

Solution is x=⅓, y=2, z=-5.

by Top Rated User (774k points)

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