consider rolling two ten-sided numbered polyhedrons( sides labelled 0-9)
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We need to add the probability of 3 followed by 1 and 1 followed by 3.

Assuming only two throws (10 possible outcomes for each throw—100 outcomes for two throws), the probability for either number on each throw is 1/10, so the two probabilities are (1/10)(1/10)+(1/10)(1/10)=1/100+1/100=2/100=1/50.

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