solve the system y-3z=-12, -2x+y+2z=5, 2x+3z=7

Solve the system: y-3z=-12, -2x+y+2z=5, 2x+3z=7
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Add eqns 2 and 3: y+5z=12; subtract 1 from this: 8z=24, so z=3. From 1 y=-12+3z=-12+9=-3; from 3 2x+9=7; 2x=-2, so x=-1. Thus x=-1, y=-3, z=3. Check the solution by substituting these values in each original equation. They check out OK.

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