I’m don’t know ive tried alot
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If there are only three zeroes, we seem to have a cubic equation.

The factors are x-(-1)=x+1, x-1, and x-2. Multiply them together:

(x+1)(x-1)(x-2)=(x²-1)(x-2)=x³-2x²-x+2=0.

This is the most basic equation. Other zeroes could be complex.

For example, (x²+1)(x³-2x²-x+2)=x⁵-2x⁴-x³+2x²+x³-2x²-x+2=

x⁵-2x⁴-x+2=0. This has the same zeroes, but there are two complex zeroes as well. On a graph you would only see the zeroes you’ve given.

The blue curve is the cubic and the red curve is the degree 5 equation. Both have the same zeroes as you can see where they intersect on the axes.

by Top Rated User (1.2m points)

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