2310+ (2×125+3×25+1×5=330₁₀+) [each number is converted into decimal using powers of 5]
3244+ (3×125+2×25+4×5+4=449₁₀+)
1333+ (1×125+3×25+3×5+3=218₁₀+)
4220 (4×125+2×25+2×5=560₁₀)
——-
12₅
200₅
2000₅
20000₅
——— (1557₁₀)
22212₅=(((2×5+2)×5+2)×5+1)×5+2= [the answer is built up one digit at a time]
((12×5+2)×5+2)×5+1)×5+2=
(62×5+1)×5+2=
311×5+2=
1557₁₀
This shows two ways of arriving at the same solution.