Answers have to be fractions. Thank You!
in Word Problem Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

If a and b are the numbers, a+b=218 and ab is maximum.

We can write b=218-a, so the product is a(218-a)=218a-a².

This can be written -(a²-218a)=-(a²-218a+109²)+109²=109²-(a-109)².

The expression is maximum 109² when (a-109)² has its minimum value of zero, that is, when a=109. (As a moves away from 109, 109² is reduced by the square of the difference between the value of a and 109, and the square is always positive.)

The maximum product is a=b=109, which can be written as an improper fraction 218/2, but reduced to its lowest terms is 109/1 or the integer 109.

by Top Rated User (1.2m points)

Related questions

1 answer
1 answer
1 answer
1 answer
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,516 questions
100,279 answers
2,420 comments
732,004 users