A frog is at the bottom of a 17-foot well. Each time the frog leaps, it moves up 3 feet. If the frog has not reached the top of the well, then the frog slides back 1 foot before it is ready to make another leap.
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3 Answers

A frog is at the bottom of a 17-foot well. Each time the frog leaps, it moves up 3 feet. If the frog has not reached the top of the well, then the frog slides back 1 foot before it is ready to make another leap.

At the end of each leap, the frog will have noved up 3 feet and moved back 1 foot, which is, in effect, a movement of 2 feet.

After 7 leaps, the frog will have moved a total of 7 * 2 = 14 feet.

Another leap will take it up another 3 feet, which means it will have reached 17 feet, before it needs to move back.

But, of course, after 17 feet it will have reached the top of the well and will immediately escape. So all ends well.

Answer: the frog needs 8 leaps to escape the well

by Level 11 User (81.5k points)
you need to minus 1ft in every jump so 3-1 + 3-1 +3-1, in short you must only add 2 in order for you not to subtract anymore. 7 jumps and the frog is now at the 14th ft of the well, his normal jump is 3ft and u will jot subtract 1ft anymore because it is already the top of the well so 14+3 = 17ft. the frog needs 8 jumps to reach the top of the well
by
Equation:

3x-1=17

3x=17+1

3x=18

3×/3=18/3

X=6

Checking:

3(6)-1=17

18-1=17

✓17=17

There are 6 leaps that frog need to escape from the 17-foot well, each time the frog leaps it moves up 3 feet then slides back 1 foot before it is ready to make another leap.
by

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