Radius of droplet=2×10⁻⁵m=0.002cm.

The volume of a droplet is (4/3)(0.002)³π cc. So (4N/3)(0.002)³π=30.

From this N=(45/2)/(0.002)³π)=2.8125×10⁹/π.

The surface area of each droplet is 4π(0.002)²=1.6π×10⁻⁵ sq cm.

Total surface area is 2.8125×10⁹/π × 1.6π×10⁻⁵ sq cm = 4.5×10⁴ sq cm = 45000 sq cm.

(If r=radius of droplet, (4/3)πr³ is its volume. If V is the volume of the gasoline, N=V/((4/3)πr³)=3V/(4πr³). Surface area of droplet=4πr². Total surface area=4πr² × 3V/(4πr³)=3V/r=90/0.002=45000 sq cm. Using algebra first greatly simplifies the calculation.)

- All categories
- Pre-Algebra Answers 12,323
- Algebra 1 Answers 25,303
- Algebra 2 Answers 10,448
- Geometry Answers 5,189
- Trigonometry Answers 2,642
- Calculus Answers 6,024
- Statistics Answers 3,025
- Word Problem Answers 10,138
- Other Math Topics 6,677

81,769 questions

86,073 answers

2,215 comments

69,559 users