The coordinates of vertex A′ of ∆A′B′C′ are . The coordinates of vertex B′ of ∆A′B′C′ are . The coordinates of vertex C′ of ∆A′B′C′ are .

Question

∆ABC is translated 2 units down and 1 unit to the left. Then it is rotated 90° clockwise about the origin to form ∆A′B′C′. 

 

Answer 1

No coords given in question. Let the following apply: A(a(x),a(y)), B(b(x),b(y)), C(c(x),c(y)).

A(a(x),a(y))➝A(a(x)-1,a(y)-2)➝A'(a(y)-2,1-a(x))

B(b(x),b(y))➝B(b(x)-1,b(y)-2)➝B'(b(y)-2,1-b(x))

C(c(x),c(y))➝C(c(x)-1,c(y)-2)➝C'(c(y)-2,1-c(x))

EXAMPLE

A(-4,5), B(5,2), C(-3,-3)➝A'(3,5), B'(0,-4), C'(-5,4)

The diagram uses the coords in the example. Track the translation and rotation of each vertex. The blue points show the results of translation and the 90° arcs show the rotation to the final position.