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asked May 14 in Algebra 1 Answers by Ashley

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1 Answer

The first equation can be reduced: x+2y=10 so 2y=10-x.

The second equation can be rearranged: 2y=26-3x.

So we have 2y on the left of each so the right hand sides are equal:

26-3x=10-x, 16=2x so x=8 and 2y=10-8=2 so y=1.

The solution is x=8 and y=1 which satisfy both equations.

answered May 15 by Rod Top Rated User (559,640 points)

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