In a raffle contest, there are 45 blue tickets and 5 gold tickets in a bag. Contestants are given three chances to draw a ticket, and each time they draw a gold ticket, they receive a prize. However, if someone draws a gold ticket on ALL THREE DRAWS, they win a new car. If the tickets are not replaced after each draw, what is the probability of winning the new car?

P(gold ticket on 1st draw)=5/50=1/10=0.10
P(assuming gold ticket on 1st draw, gold ticket on 2nd draw)=4/49=0.08
P(assuming gold ticket on 1st and 2nd draw, gold ticket on 3rd draw)=3/48=1/16=0.06

P(grand prize) = ________?

in Word Problem Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

The combined probability is (5/50)(4/49)(3/48)=1/(10×49×4)=1/1960=0.0005102 approx or 0.05102%.

The quoted approximations produce 0.048%.

by Top Rated User (781k points)

Related questions

1 answer
1 answer
Welcome to, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
85,299 questions
90,692 answers
98,410 users