Y= 49.65 - .0398x Round to the nearest 10th when applicable (1 decimal) What is the predicted number of wins for a team that allowed 750 runs? If the team that allowed 750 runs actually had 23 wins, what would the residual be?
asked Apr 11 in Statistics Answers by anonymous

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According to the given equation, the predicted number of wins is 19.8.

This is 3.2 below the actual number of wins. Therefore the residual is 3.2.

(The standard deviation given is around 13% of the mean. The deviation of 3.2 is about 17% of the predicted number of wins, so the variation is 4% higher compared to the statistics.)

answered Apr 11 by Rod Top Rated User (582,800 points)

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