5 log6 (7w +1) + 3 = 13
asked Mar 8 in Algebra 1 Answers by anonymous

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Assume log6(7w+1) means log₆(7w+1) (log to base 6 of 7w+1).

5log₆(7w+1)=13-3=10

log₆(7w+1)=10/5=2

6^(log₆(7w+1))=6²=36

7w+1=36

7w=35

w=5
answered Mar 9 by Rod Top Rated User (592,640 points)

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