X^2-5x-14x over 2x^2-8

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1 Answer

2x^2-8 factorises: 2(x-2)(x+2) and x^2-5x-14 factorises: (x-7)(x+2).

The common factor x+2 cancels out when the two expressions are divided with the result: (x-7)/(2(x-2)) or (x-7)/(2x-4).

by Top Rated User (1.2m points)

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